How many moles of K3PO4 are required to react completely with 4.5 moles of CaCl2
2K3PO4 + 3CACl -> Ca3(PO4)2 + 6KCL
Chemistry - GK, Tuesday, June 16, 2009 at 8:21pm
2K3PO4 + 3CaCl2 -> Ca3(PO4)2 + 6KCL
We use the coefficients in the chemical equation to set up:
(4.5 mol. CaCl2)(2 mol K3PO4 / 3 mol CaCl2) = ?? _____ moles K3PO4
Notice I used DOUBLE labels. Do the unit cancellation which can't be shown here.
NOTE: The above method I used is called the unit factor, factor label, or dimensional analysis method. All chemistry textbooks show it in the answered examples. I highly recommend it.