Wednesday

April 16, 2014

April 16, 2014

Posted by **Peter** on Tuesday, June 16, 2009 at 6:22pm.

3^(2-x) = 2^x

Thanks.

- trig -
**Reiny**, Tuesday, June 16, 2009 at 6:29pmtake the logs of both sides

log (3^(2-x)) = log (2^x)

(2-x)log3 = xlog2

2log3 - xlog3 = xlog2

2log3 = xlog2 + xlog3

2log3 = x(log2 + log3)

x = 2log3/(log2 + log3)

or x = 2log3/log6

- trig -
**Chris**, Wednesday, June 17, 2009 at 1:08amOk, I'm kind of confused.

A log's base typically 10 right? Why would you write log 3^(2-x)? Shouldn't it be log(sub3) 2-x) ?

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