Maths
posted by Lucy on .
Given that y=x^2+2x3
When x is 3 what is y?
Is the ans 0?
When x is 1 what is y?
Is the ans 0?

if x=3, then y=3, not zero:
y=3^263
y=663
y=3
Does this make sense?
if x=1, then y=0, you are correct:
y=1^2+23
y=1+23
y=33
y=0
Does this make sense?
Hope this helps!! :) 
Sally has made a mistake. (3)^2 = 9 not 6.
y=3^263 = 9  6  3 = 0
The second value solution is correct.
I hope this helps a little more. Thanks for asking.