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find the max point on the graph f(x) = -1/3x^3 + 3x^2 - 5x

  • calculus -

    The maximum is where the first derivative is zero, provided the second derivative is negative there.

    Solve the equation
    f'(x) = -x^2 +6x -5 = 0
    -(x-5)(x-1) = 0

    x = 5 and x = 1 are either maxima or minima. Use the second derivative test to see which is which.

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