Posted by Sandhya on Tuesday, June 16, 2009 at 4:36am.
A bullet of mass ‘m’ traveling horizontally at a speed ‘v’ embeds itself in the centre of a block of wood of mass ‘M’, which is suspended by a light vertical string of length ‘l’. What would be the maximum inclination of the string with the vertical?

physics  drwls, Tuesday, June 16, 2009 at 5:16am
After the bullet gets embedded in the block, the block acquires velocity V given by
mv = (m+M) V
V = [m/(m+M)] v
Then the pendulum swings to a height H while total energy is conserved:
gH = V^2/2 = [m/(m+M)]^2 v^2/2
If the maximum inclination angle of the swing is A and the string length is l,
l (1  cos A) = H
Solve for A
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