Monday

July 28, 2014

July 28, 2014

Posted by **Danny** on Monday, June 15, 2009 at 6:38pm.

My answer: (pi/4)+2(pi)k, (7pi/4) + 2(pi)k

Solve 2cos^2 x-5cosx+2=0 for principal values of x.

My answer: 60 and 300 degrees

- Pre Cal -
**Reiny**, Monday, June 15, 2009 at 8:43pmVery good, I agree with both answers.

Is there any reason why you gave the first answers in radians and the second in degrees?

**Related Questions**

Pre Cal. - So I posted these...but no one answered them. Are they right? Solve ...

Advanced Math - Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x. ...

pre-cal - solve for all values in [0,2pie) 2cos^2x-5sinx+1=0

Precalculus check answers help! - 1. Which expression is equivalent to cos ...

trig - Solve for all real values of x 3cos2x - 5cosx = 1

Math - Solve 4sin^2x + 4(squareroot of 2)cosx -6 for all real values of x.

Pre-calculus - solve 4 sin^2x + 4 sqrt 2 cos x-6=0 for all real values of x. ...

pre-cal - solve for all values in [0,2pie) 2sin^2x-1=0

Trigonometry desperate help, clueless girl here - 2. solve cos 2x-3sin x cos 2x...

math/cal/trig solve for t - solve for t: 0=4sin(2t)cos(2t)-sin(2t)