Pre Cal
posted by Danny .
Solve 4sin^2 x + 4sqrt(2) cos x6 = 0 for all real values of x.
My answer: (pi/4)+2(pi)k, (7pi/4) + 2(pi)k
Solve 2cos^2 x5cosx+2=0 for principal values of x.
My answer: 60 and 300 degrees

Very good, I agree with both answers.
Is there any reason why you gave the first answers in radians and the second in degrees?