Posted by **Danny** on Monday, June 15, 2009 at 6:38pm.

Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x.

My answer: (pi/4)+2(pi)k, (7pi/4) + 2(pi)k

Solve 2cos^2 x-5cosx+2=0 for principal values of x.

My answer: 60 and 300 degrees

## Answer This Question

## Related Questions

- Pre Cal. - So I posted these...but no one answered them. Are they right? Solve ...
- Advanced Math - Solve 4sin^2 x + 4sqrt(2) cos x-6 = 0 for all real values of x. ...
- pre-cal - solve for all values in [0,2pie) 2cos^2x-5sinx+1=0
- Precalculus check answers help! - 1. Which expression is equivalent to cos ...
- trig - Solve for all real values of x 3cos2x - 5cosx = 1
- Math - Solve 4sin^2x + 4(squareroot of 2)cosx -6 for all real values of x.
- Pre-calculus - solve 4 sin^2x + 4 sqrt 2 cos x-6=0 for all real values of x. ...
- Maths integration - Please help! These 2 questions are very similar, and i tried...
- Trigonometry - Checking my work - Find the sum of the three smallest positive ...
- pre-cal - solve for all values in [0,2pie) 2sin^2x-1=0

More Related Questions