What gravitational force do yhe two protons in the helium nucleus exert on each other? There separation is approximately 1.0 fm.

I know that 1 fm is 10^-15 m i didn't know if that was how you figured it out to get it to N?

To get the electrostatic force forcing the two protons apart, use Coulomb's Law

F = k e^2/r^2

where r = 10^-15 m and e is the proton (and electron) charge, in Coulomb's. The value of the constant k should be available in your notes or textbook, or can easily be found by googling "Coulomb's law"... or read
http://www.glenbrook.k12.il.us/gbssci/phys/Class/estatics/u8l3b.html

The reason the nucleus stays together is that there is an addition attractive force between bosons (protons and neutrons) called "the strong force"

To calculate the gravitational force between two objects, you can use Newton's law of universal gravitation. The formula for gravitational force (F) is:

F = (G * m1 * m2) / r^2

where:
- G is the gravitational constant (approximately 6.67430 x 10^-11 N*m^2/kg^2)
- m1 and m2 are the masses of the two objects (in this case, protons)
- r is the separation between the centers of the two objects

Given that the separation between the two protons is approximately 1.0 fm (femtometer), which is equal to 1.0 x 10^-15 m, we can calculate the gravitational force.

Substituting the values into the formula, we have:

F = (6.67430 x 10^-11 N*m^2/kg^2) * (1.67 x 10^-27 kg) * (1.67 x 10^-27 kg) / (1.0 x 10^-15 m)^2

Calculating this expression will give you the gravitational force between the two protons in the helium nucleus.