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March 31, 2015

March 31, 2015

Posted by **Rachale** on Sunday, June 14, 2009 at 11:34pm.

I need to find the Quotient Function of the following:

Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:

a. (f/g)(-root3)

b. (g/f)(-1/2)

- Algebra -
**drwls**, Monday, June 15, 2009 at 12:10amI have never heard of the term "quotient function". From your description of what it is,I would suggest that you just compute f(x) and g(x) for the x value you are given, and take the ratio.

f(-1/2) = -3 1/4

g(-1/2) = 0

f/g (-1/2) = infinity

The "quotient function" is just f(x)/g(x), which you can write as a ratio of the two functions

- Algebra -
**Rachale**, Monday, June 15, 2009 at 12:21amWhat about A? Is there a solution for it?

Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:

a. (f/g)(-root3)

- Algebra -
**Rachale**, Monday, June 15, 2009 at 12:25amDid you combine the two problems? These are two separate functions.

I need to find the Quotient Function of the following:

Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:

a. (f/g)(-root3)

b. (g/f)(-1/2)

- Algebra -
**drwls**, Monday, June 15, 2009 at 9:44amf/g is (x^2 -3)/(2x+1)

Plug in -sqrt3 for x and compute

g/f is (2x+1)/(x^2 -3)

Plug in -1/2 for x and compute

- Algebra -
**sophie**, Thursday, October 4, 2012 at 5:23pminead help on math homwork

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