That is not what the ? is asking. The ? is asking about how to get the quotient function, not the composite as you solved for. Can you please show us how to get the quotient function solution? Thanks!
I need to find the Quotient Function of the following:
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
b. (g/f)(-1/2)
I have never heard of the term "quotient function". From your description of what it is,I would suggest that you just compute f(x) and g(x) for the x value you are given, and take the ratio.
f(-1/2) = -3 1/4
g(-1/2) = 0
f/g (-1/2) = infinity
The "quotient function" is just f(x)/g(x), which you can write as a ratio of the two functions
What about A? Is there a solution for it?
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
Did you combine the two problems? These are two separate functions.
I need to find the Quotient Function of the following:
Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:
a. (f/g)(-root3)
b. (g/f)(-1/2)
f/g is (x^2 -3)/(2x+1)
Plug in -sqrt3 for x and compute
g/f is (2x+1)/(x^2 -3)
Plug in -1/2 for x and compute
inead help on math homework
Sure! To find the quotient function, we need to divide the functions f(x) and g(x). Let's start with the given functions:
f(x) = x^2 - 3
g(x) = 2x + 1
a. To find (f/g)(-√3), we need to substitute (-√3) into f(x) and g(x) and then divide the results. So let's begin by substituting (-√3) into f(x):
f(-√3) = (-√3)^2 - 3
= 3 - 3
= 0
Now let's substitute (-√3) into g(x):
g(-√3) = 2(-√3) + 1
= -2√3 + 1
Finally, divide f(-√3) by g(-√3):
(f/g)(-√3) = f(-√3) / g(-√3)
= 0 / (-2√3 + 1)
= 0
Therefore, the quotient function (f/g)(-√3) is equal to 0.
b. Similarly, to find (g/f)(-1/2), we need to substitute (-1/2) into g(x) and f(x), and then divide the results. Let's begin by substituting (-1/2) into g(x):
g(-1/2) = 2(-1/2) + 1
= -1 + 1
= 0
Now let's substitute (-1/2) into f(x):
f(-1/2) = (-1/2)^2 - 3
= 1/4 - 3
= -11/4
Finally, divide g(-1/2) by f(-1/2):
(g/f)(-1/2) = g(-1/2) / f(-1/2)
= 0 / (-11/4)
= 0
Therefore, the quotient function (g/f)(-1/2) is also equal to 0.
In both cases, the quotient function evaluated at the given values is 0.