Posted by scooby9132002 on Sunday, June 14, 2009 at 6:33pm.
in 1920 the record for a certain race was 46.9 sec. In 1990 it was 45.5 sec. let R(t) = the record in the race and t = the number of years since 1920
1.)find a linear function that fits this data?
2.) use a function to predict the record in 2003 and 2006.
3.) find the year when the record will be 44.98 sec.
I think number 1 is 46.9

math (am i correct)  Damon, Sunday, June 14, 2009 at 6:43pm
Record = m (year 1920) + b
where year 1920 = t so
R = m t + b
46.9 = m (0) + b
so b = 46.9
in 1990, t = 1990  1920 = 70
so
45.5 = m (70) + 46.9
m = .02
so
R = .02 t + 46.9
for 2003 for example
t = 2003  1920 = 83
so
R = .02(83)+46.9
R = 45.24

math (am i correct)  Quidditch, Sunday, June 14, 2009 at 6:49pm
1 is not 46.9.
Question 1 asks you to find a linear function that fits the data.
Find a function f(t) where t is the number of years since 1920. There are two points given.
1920, 46.9s
1990, 45.5s
Or, for t expressed as years since 1920...
0 years, 46.9s
70 years, 45.5s
for a linear function, y = mx + b
Where m is the slope and b is the y axis intercept.
The slope, m, is (y2  y1)/(x2  x1)
or
(45.5  46.9)/(70  0)
Calculate this value for the slope.
The y intercept is at x=0 which is already given as one of the points (0, 46.9)

math (am i correct)  scooby9132002, Sunday, June 14, 2009 at 6:55pm
ok so what is the predicted record for 2006?
in what year will the predicted record be 44.98 seconds?

math (am i correct)  Damon, Sunday, June 14, 2009 at 7:08pm
Scooby, we are not going to do everything for you.
From the way I did 2003 you should be able to do the rest.
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