Posted by **Ken** on Sunday, June 14, 2009 at 1:57pm.

Given the equation:

6CO2(g) + 6H2O(l) -> C6H12O6(s) + 6O2(g)

What is the minimum number of liters of CO2(g), measured at STP, needed to produce 32.0 grams of oxygen?

1) 264 L

2) 32.0 L

3) 192 L

4) 22.4 L

How do I solve?

- Chemistry -
**GK**, Sunday, June 14, 2009 at 9:04pm
32.0 g O2 = 1 mole O2

1 mole O2 = 22.4 L

The mole ratio shown by the coefficients in the chemical equation is the same as the volume (liters) ratio. So,

6 L of CO2 produce 6 L O2, or

1 L CO2 make 1 L O2

How many liters CO2 would produce 22.4 L O2 ??

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