Sunday

April 20, 2014

April 20, 2014

Posted by **sarah** on Sunday, June 14, 2009 at 1:40pm.

- physics -
**drwls**, Sunday, June 14, 2009 at 2:29pmForce x distance driven =

Potential energy of the lifted weight

= (413)(9.8)(1.4) J

The distance X that the pile gets driven each time is (1/2)*(pile impact velocity)*time

The impact velocity of the pike is

V = sqrt(2gH)

Compute V, X, and then solve for the force.

- physics -
**drwls**, Sunday, June 14, 2009 at 3:42pmI just realized that this problem can be solved more directly using momentum considerations. The answer should be the same.

(Force)(stopping time)

= momentum at impact = M V

F = M V/(0.024 s)

V = sqrt(2gH), as before

- physics -
**alicia**, Saturday, July 2, 2011 at 7:11pmA spelunker (cave explorer) drops a stone from rest into a hole. The speed of sound is 343 m/s in air, and the sound of the stone striking the bottom is heard 3.87 s after the stone is dropped. How deep is the hole?

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