Posted by sarah on Sunday, June 14, 2009 at 1:40pm.
Force x distance driven =
Potential energy of the lifted weight
= (413)(9.8)(1.4) J
The distance X that the pile gets driven each time is (1/2)*(pile impact velocity)*time
The impact velocity of the pike is
V = sqrt(2gH)
Compute V, X, and then solve for the force.
I just realized that this problem can be solved more directly using momentum considerations. The answer should be the same.
(Force)(stopping time)
= momentum at impact = M V
F = M V/(0.024 s)
V = sqrt(2gH), as before
A spelunker (cave explorer) drops a stone from rest into a hole. The speed of sound is 343 m/s in air, and the sound of the stone striking the bottom is heard 3.87 s after the stone is dropped. How deep is the hole?
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