Please help. I need to find the quotient function of the following:

Given that f(x)=x^2-3 and g(x)=2x+1 find each of the following if it exists:

a. (f/g)(-root3)

b. (g/f)(-1/2)

I asnwered this question last week.

I was not here last week. Can you please help? Thanks.

http://www.jiskha.com/display.cgi?id=1244864678

This problem is typed exactly the same as "Breanna" did a few days ago

To find the quotient function, you need to divide the two given functions: f(x) and g(x).

a. (f/g)(-√3)
To find (f/g)(-√3), substitute -√3 into both f(x) and g(x), and divide f(x) by g(x).

Step 1: Evaluate f(-√3)
Substitute -√3 into f(x) = x^2 - 3.
f(-√3) = (-√3)^2 - 3
= 3 - 3
= 0

Step 2: Evaluate g(-√3)
Substitute -√3 into g(x) = 2x + 1.
g(-√3) = 2(-√3) + 1
= -2√3 + 1

Step 3: Divide f(-√3) by g(-√3)
(f/g)(-√3) = f(-√3) / g(-√3)
= 0 / (-2√3 + 1)
= 0

Therefore, (f/g)(-√3) is equal to 0.

b. (g/f)(-1/2)
To find (g/f)(-1/2), substitute -1/2 into both f(x) and g(x) and divide g(x) by f(x).

Step 1: Evaluate f(-1/2)
Substitute -1/2 into f(x) = x^2 - 3.
f(-1/2) = (-1/2)^2 - 3
= 1/4 - 3
= -11/4

Step 2: Evaluate g(-1/2)
Substitute -1/2 into g(x) = 2x + 1.
g(-1/2) = 2(-1/2) + 1
= -1 + 1
= 0

Step 3: Divide g(-1/2) by f(-1/2)
(g/f)(-1/2) = g(-1/2) / f(-1/2)
= 0 / (-11/4)
= 0

Therefore, (g/f)(-1/2) is equal to 0.