Posted by AP Physics on Saturday, June 13, 2009 at 8:32pm.
hi I need help on this proof
ok I'm tyring to prove that
v^2 = v^20 + 2a(x x0)
where the zeros are subscripts
ok the first step my book says is
start out with
x = x0 + average velocity (t)
then plug in average velocity
x = x0 + (2^1(v + v0))t
ok and the next line it says
solve for t
and the next formula it shows
is
t = a^1(v  v0)
ok how did you go from that line to this one?
Please show me
what happened to the two?
were did the a come from
I don' get it
Thanks!

AP Physics  Damon, Saturday, June 13, 2009 at 8:47pm
I do not blame you but I will try.
V^2 = Vo^2 + 2 a (XXo)
is where you want to go
ok
X = Xo + (V+Vo)t/2
V+Vo = 2 (XXo)/t
Now what you seem to be missing is
V = Vo + a t
which you are supposed to know, the definition of constant acceleration (change in velocity = acceleration times time)
so
t =(VVo)/a
then
(V+Vo) = 2(XXo) a /(VVo)
so then
V^2Vo^2 = 2 (XXo) a

AP Physics  Damon, Saturday, June 13, 2009 at 8:48pm
This is a really, really, klutzy way to do this !!!
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