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April 2, 2015

April 2, 2015

Posted by **AP Physics** on Saturday, June 13, 2009 at 8:32pm.

ok I'm tyring to prove that

v^2 = v^20 + 2a(x -x0)

where the zeros are subscripts

ok the first step my book says is

start out with

x = x0 + average velocity (t)

then plug in average velocity

x = x0 + (2^-1(v + v0))t

ok and the next line it says

solve for t

and the next formula it shows

is

t = a^-1(v - v0)

ok how did you go from that line to this one?

Please show me

what happened to the two?

were did the a come from

I don' get it

Thanks!

- AP Physics -
**Damon**, Saturday, June 13, 2009 at 8:47pmI do not blame you but I will try.

V^2 = Vo^2 + 2 a (X-Xo)

is where you want to go

ok

X = Xo + (V+Vo)t/2

V+Vo = 2 (X-Xo)/t

Now what you seem to be missing is

V = Vo + a t

which you are supposed to know, the definition of constant acceleration (change in velocity = acceleration times time)

so

t =(V-Vo)/a

then

(V+Vo) = 2(X-Xo) a /(V-Vo)

so then

V^2-Vo^2 = 2 (X-Xo) a

- AP Physics -
**Damon**, Saturday, June 13, 2009 at 8:48pmThis is a really, really, klutzy way to do this !!!

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