Posted by STACEY on Saturday, June 13, 2009 at 8:16pm.
You mean factor
a(2x+3y)-b(2x+3y)
= (a-b)(2x+3y)
5(x^2-4)
= 5 (x-2)(x+2)
(3x-5)(x+3)
first one is "grouping"
2ax+3ay-2bx-3by
= a(2x+3y) - b(2x+3y)
= (2x+3y)(a-b)
second, common factor then difference of squares
5x^2-20
= 5(x^2 - 4)
= 5(x+2)(x-2)
third, general quadratic
3x^2+4x-15
= (3x-5)(x+3)
looks like you got your answer by
adding 3x^2 + 4x to get 7x^3
that is just unforgivable!
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