posted by D. on .
Two dice are rolled. Find the probability that a multiple of three is rolled on one die and an even number is rolled on the second die.
for the even number:3/6. i'm not so sure if you have to reduce this to lowest terms.
3 and 6 are multiples of 3. The probability the either one or the other events would occur is obtained by adding the probability of the individual events. Probability = 1/6 + 1/6 = 2/6 = 1/3
2, 4 and 6 are even numbers = 1/6 + 1/6 + 1/6 = 3/6 = 1/2
The probability that both/all events would occur is found by multiplying the probability of the individual events.
I hope this helps. Thanks for asking.