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September 30, 2014

September 30, 2014

Posted by **Maya** on Saturday, June 13, 2009 at 10:42am.

- Math -
**Reiny**, Saturday, June 13, 2009 at 10:56amYou could have EO, or OE

prob(EO) = (/12)(1/2) = 1/4

prob(OE) = (/12)(1/2) = 1/4

so prob of one even one odd = 1/4 + 1/4 = 1/2

Another way:

make a chart with DIE1 on top and DIE2 on the side.

there will be 36 outcomes, 18 even sums and 18 odd sums.

(notice that the sum of an even + odd = odd, but the sum of either two evens or two odds is even)

so prob = 18/36 = 1/2

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