I will give you the formulas for the problems,
for any two points (a,b) and (c,d)
1. Midpoint = ((a+c)/2,(b+d)/2)
2. Distance between the two points
= √[(a-c)^2 + (b-d)^2]
3. slope = (b-d)/(a-c)
compare (a,b) and (c,d) with your given points and evaluate.
Let me know what you get
This has got to be in your text book!
The midpoint is the average x and the average y
Xav = (3+9)/2 = 6
Yav = (-1+2)/2 = 1/2
(6 , 1/2)
d^2 = [(Y2-Y1)^2 + (X2-X1)^2 ]
= [ 3^2 + 6^2 ]
= [ 9 + 36 }
d = sqrt 45 = 3 sqrt 5
slope = (Y2-Y1) / (X2-X1)
I think you can carry that division out
(x1 + x2)/2, y1 + y2)/2 =
3+9/2 = 12/2 = 6
-1+2/2 = 1/2 = .05
This is what I got for the mid point. is this correct? I got 6 for the first set of numbers, and .05 for the second. How do I determine the mid point?
I think I figured it out. The answer can contain a fraction along with whole numbers. So i guess the mid point would be (6,.05) correct?
"Anonymous" already gave you the answer.
why don't you just replace the values ?
you started with ...
((x1 + x2)/2, (y1 + y2)/2) , notice I corrected your "bracket errors"
you had .05
1/2 is .5 not .05
oops I misplaced the decimal. So yea (6,0.5) is the solution I came up with.
Now I will work on the distance and slope parts. Hopefully they will be correct to!
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