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October 31, 2014

October 31, 2014

Posted by **angie** on Saturday, June 13, 2009 at 12:50am.

x^2=8x-41

(4x-1)(2x+6)=3x

45-t^2=0

(3x-6)^2=33

- math -
**drwls**, Saturday, June 13, 2009 at 6:47amThey want you to solve for the unknown variable. You need to rewrite the equation in quadratic form

ax^2 + bx + c = 0, first of all.

y^2 -6x = -7 can be rewritten

y^2 -6x +7 = 0

Use the quadratic formula to solve.

http://www.purplemath.com/modules/quadform.htm

y = [6 +/-sqrt(36-28)]/2

= 3 +/- sqrt2

You do the others; someone will check your work if you make the effort.

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