Posted by Anonymous on .
What mass of lithium (in g) is required to react completely with 59.1 mL of gas at STP? given the equation 6Li+N2=2Li3

chem 
drwls,
Your reaction equation should be
6Li + N2 = 2 Li3N
59.1 ml at STP is
(59.1*10^3 l)/(22.4 l/mol)
= 2.64*10^3 moles of N2.
That will react with 6 times as many moles of Li. Compute the mass of that.