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What mass of lithium (in g) is required to react completely with 59.1 mL of gas at STP? given the equation 6Li+N2=2Li3

  • chem - ,

    Your reaction equation should be
    6Li + N2 = 2 Li3N

    59.1 ml at STP is
    (59.1*10^-3 l)/(22.4 l/mol)
    = 2.64*10^-3 moles of N2.
    That will react with 6 times as many moles of Li. Compute the mass of that.

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