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Algebra

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State the center and the radius of the circle represented by the equation

(x + 1)^2 + (y – 5)^2 = 64

  • Algebra - ,

    in the general equation of a circle
    (x-h)^2 + (y-k)^2 = r^2
    the centre is (h,k) and the radius is r

    can you match this with your given equation?

  • Algebra - ,

    ok based on that I would say the radius is 8 cause 8*8 = 64 and the center is (1,5)? Or do the signs change because of the equation
    (x-h)^2 + (y-k)^2 = r^2 making the center (-1,5)?

  • Algebra - ,

    radius is correct,
    the centre is (-1,5)

  • Algebra - ,

    That is what I thought, so the standard form would be

    (x-(-1]^2 + (y-5)^2 = 64

  • Algebra - ,

    yes,
    I just mentally change the sign I see in the bracket

  • Algebra - ,

    Great! Thanks for the help! So R= 8 and the center is (-1,5) got it! Thanks again!

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