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I am trying to answer a bunch of lab questions about a lab I did and am stuck on finding the morality of the diluted vinegar solution? Can anyone help me? (I hope I gave enough info)

Here where the lab procedures that I already went through:

Transfer 10mls (Vc)of vinegar to a 100mL volumetric flask (Vd). Fill the volumetric flask to the line with water. Using a pipet, transfer 10mLs of the diluted vinegar solution to a 125mL volumetric flask. Add 25mLs of distilled water and 2 drops of phenolphthalein indicator solution. Obtain a buret and fill it with 50mLs of sodium hydroxide

When the solution turns from colorless to pink, record how much (by difference) NaOH was added. (This occurred at 26.10 mLs)

Here are the steps that I am given to help solve my Homework:

-Using the morality of NaOH determined above (This was the first part of the Homework and I already determined that the Morality of NaOH was 31.90 mLs or .0319 L) and the volume of NaOH used, find the moles of NaOH. (I took .02610/.0307=.85016)

-Convert the moles of NaOH to moles of acetic acid using the balanced equation. (The moles should be the same for both .85016)

-Divide the moles of acetic acid by the volume of solution that contained those moles of acetic acid. (This is where I am stuck)

-Use the dilution formula to find the concentrated morality of acetic acid in vinegar.

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