I am trying to answer a bunch of lab questions about a lab I did and am stuck on finding the morality of the diluted vinegar solution? Can anyone help me? (I hope I gave enough info)
Here where the lab procedures that I already went through:
Transfer 10mls (Vc)of vinegar to a 100mL volumetric flask (Vd). Fill the volumetric flask to the line with water. Using a pipet, transfer 10mLs of the diluted vinegar solution to a 125mL volumetric flask. Add 25mLs of distilled water and 2 drops of phenolphthalein indicator solution. Obtain a buret and fill it with 50mLs of sodium hydroxide
When the solution turns from colorless to pink, record how much (by difference) NaOH was added. (This occurred at 26.10 mLs)
Here are the steps that I am given to help solve my Homework:
-Using the morality of NaOH determined above (This was the first part of the Homework and I already determined that the Morality of NaOH was 31.90 mLs or .0319 L) and the volume of NaOH used, find the moles of NaOH. (I took .02610/.0307=.85016)
-Convert the moles of NaOH to moles of acetic acid using the balanced equation. (The moles should be the same for both .85016)
-Divide the moles of acetic acid by the volume of solution that contained those moles of acetic acid. (This is where I am stuck)
-Use the dilution formula to find the concentrated morality of acetic acid in vinegar.
To find the molarity of the diluted vinegar solution, you need to follow these steps:
Step 1: Find the moles of NaOH used
Using the molarity of NaOH (0.0319 L) and the volume of NaOH used (26.10 mL or 0.02610 L), you can calculate the moles of NaOH as:
Moles of NaOH = Molarity * Volume
Moles of NaOH = 0.0319 L * 0.02610 L = 0.00083319 moles
Step 2: Convert moles of NaOH to moles of acetic acid
Since the balanced equation between NaOH and acetic acid is 1:1, the moles of acetic acid will be the same as the moles of NaOH:
Moles of acetic acid = 0.00083319 moles
Step 3: Divide moles of acetic acid by the volume of solution
Your 10 mL of diluted vinegar solution contains the same amount of acetic acid as the moles calculated in the previous step. Therefore, you divide the moles of acetic acid by the volume of the solution:
Molarity of acetic acid = Moles of acetic acid / Volume of solution
Molarity of acetic acid = 0.00083319 moles / 0.010 L = 0.083319 M
Step 4: Use the dilution formula to find the concentrated molarity of acetic acid in vinegar
You started with 10 mL of vinegar and diluted it to 125 mL. The diluted vinegar solution is 1/12.5 times more dilute compared to the original vinegar solution. Therefore, you need to multiply the molarity of the diluted acetic acid by the dilution factor to find the molarity of the concentrated acetic acid in vinegar:
Molarity of concentrated acetic acid = Molarity of diluted acetic acid * Dilution factor
Molarity of concentrated acetic acid = 0.083319 M * 12.5 = 1.04149 M
So, the molarity of the diluted vinegar solution is 0.083319 M, and the concentrated molarity of acetic acid in vinegar is 1.04149 M.