posted by Z32 .
Let f be the function defined by f(x)=2x+11-3e^x
If the equation of the tangent line to the graph of f at the point (0,8) is given by y=mx+b then:
For the standard line equation,
m is the slope of the line
b is the y intercept (where x=0)
Take the derivative of the equation. Use that to find the slope of the tangent at (0,8). Once you have the slope and one point (0,8) you can solve for the b.
I just need help finding the derivative of f(x). The 3e^x is tripping me out.
y = 3e^x
dy/dx = 3 e^x
d/dx e^u = e^u du/dx