Posted by G on .
Solve z/6+14=z/6+25z/6 for z.
z/6+14=z/6+25z/6
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z/6=z/6+11z/6
I have tried this problem a few times. The book says the anwer is z=66. I understand you would now take the 6 from the left side and multiply the 11 to get the 66. I am not clear what to do about the two z/6's.

Algebra 
Reiny,
ok to
z/6=z/6+11z/6 , the z/6 cancel each other
then
z/6 = 11 , multiply by 6
z = 66