Posted by G on .
Solve z/6+14=z/6+25-z/6 for z.
I have tried this problem a few times. The book says the anwer is z=66. I understand you would now take the 6 from the left side and multiply the 11 to get the 66. I am not clear what to do about the two z/6's.
z/6=z/6+11-z/6 , the z/6 cancel each other
z/6 = 11 , multiply by 6
z = 66