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November 28, 2014

November 28, 2014

Posted by **G** on Thursday, June 11, 2009 at 10:25pm.

z/6+14=z/6+25-z/6

___-14____-14

________________

z/6=z/6+11-z/6

I have tried this problem a few times. The book says the anwer is z=66. I understand you would now take the 6 from the left side and multiply the 11 to get the 66. I am not clear what to do about the two z/6's.

- Algebra -
**Reiny**, Thursday, June 11, 2009 at 10:49pmok to

z/6=z/6+11-z/6 , the z/6 cancel each other

then

z/6 = 11 , multiply by 6

z = 66

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