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December 20, 2014

Homework Help: chemistry

Posted by Chemically Confused on Thursday, June 11, 2009 at 12:31pm.

Can someone give me some directions as to how to reach the answer for this problem:

A 0.608g sample of fertilizer contained nitrogen as ammonium sulfate,
(NH4)2 SO4(s)+2NaOH(aq)-->Na2SO4(aq)+ 2H2O(l)+2NH3(g)

The ammonia was collected in 46.3 mL of 0.213 M HCL (hydrochloric acid), with which it reacted.

NH3(g)+HCL(aq)-->NH4Cl(aq)

This solution was titrated for excess hydrochloric acid with 44.3 mL of 0.128 M NaOH

NaOH(aq)+HCL(aq)NaCL(aq)+H2O(l)

What is the percentage of nitrogen in the fertilizer?

The answer is 9.66%

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