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Posted by **just wondering** on Tuesday, June 9, 2009 at 8:19pm.

- math -trig -
**Reiny**, Tuesday, June 9, 2009 at 9:28pmnice question!

lets do some geometric construction.

Draw the original triangle, label it ABC with a=10, b=7 and c=8

draw the larger triangle DEF with a 1 unit space between the sides, so that angle A = angle D etc.

let's concentrate at the angle B corner.

Extend AB to meet EF at P

From B drop a perpendiclar to meet EF at Q

draw a perpendicular from B to meet DE at R

Now for the math:

find angle ABC using the cosine law

in the right-angled triangle BPQ, clearly angle ABC = angle BPQ, BQ=1 and tan(angle BPQ)= 1/PQ

so you can find PQ

similarly in triangel REP

angle REP = angle ABC, RP = 1, and

sin(angle REP) = 1/EP

so we can find EP

So now we find the extension of the original side BC at angle B

now by the Sine Law we can now find angle C and repeat the same steps at that vertex.

Finally we can find EF by adding 10 + extension at angle B + extension at angle C

so we now have EF and we can use the similar triangle ratio to find ED and EF

I sure hope somebody has a faster way of doing this.

- math -trig -
**MathMate**, Tuesday, June 9, 2009 at 9:40pmThis seems to me a very original question.

The permimeter of the garden is easy enough, simply 10+7+8=25 m.

To calculate the size of the outer triangle which is at 1 m. offset from the garden, I would first calculate the inscribed radius, r. Since the inscribed circle is tangential to all three sides of the inner triangle (garden), the inscribed radius of the outer triangle is therefore one metre more, R=r+1.

Thus the ratio (r+1)/r is the same as the ratio of the permimeter of the inner and outer triangles.

To calculate the inscribed radius, we can use a formula very similar to Heron's formula for the area of a triangle having side lengths a, b and c.

Let s=(a+b+c)/2

r = sqrt((s-a)(s-b)(s-c)/s)

Thus, the perimeter of the outer triangle is

R = r+1 = (10+7+8)*(r+1)/r

Can you carry on from here?

- math -trig -
**MathMate**, Tuesday, June 9, 2009 at 9:42pmReference for the inscribed circle radius given the three sides a, b, and c:

http://www.analyzemath.com/Geometry_calculators/radius_inscribed_circle.html

- math -trig -
**just wondering**, Tuesday, June 9, 2009 at 9:58pmi got most of what u guys said, bt i need the answer speacially cuz i keep on getting diff answers....god this question is long

- math -trig -
**Ms. Sue**, Tuesday, June 9, 2009 at 10:06pmPlease post the answers you get -- and I'm sure one of them will help you find which one is correct.

- math -trig -
**MathMate**, Tuesday, June 9, 2009 at 10:39pmFor the inner perimeter, I have (10+7+8)=25

For the outer, I have between 36 and 37.

Post your answer (better still your workings) and we'll be glad to verify it.

- math -trig -
**Reiny**, Tuesday, June 9, 2009 at 10:51pmBTW, I worked out the answer my way and MathMate's way and got

36.23666.. (correct to 5 decimals) both ways.

MathMate, I haven't seen that formula in 45 years.

- math -trig -
**MathMate**, Tuesday, June 9, 2009 at 11:20pmI have come across it somewhere. All I knew earlier was that it exists. I had to search for it and was glad that I found it!

The question appeared very innocuous but it is original. It took a bit of gray matter juice from both of us!

- math -trig -
**MathMate**, Tuesday, June 9, 2009 at 11:25pmOops, I just found out why just wondering is still wondering. There is a mistake on the last line for the outer perimeter:

Outer perimeter

= inner perimerter*(R/r)

= (10+7+8)*(r+1)/r

Sorry for the oversight.

- math -trig -
**Reiny**, Tuesday, June 9, 2009 at 11:28pmThis is why I answer math questions on this site.

Helping with math homework is "recreation" for me, and every once in a while you come across a little gem like this.

- math -trig -
**Damon**, Wednesday, June 10, 2009 at 8:57amHey, that is really cool !

- math -trig -
**just wondering**, Thursday, June 11, 2009 at 3:17pmokay so my answer was 35 but the back of the book says it is 37

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