Posted by **Sarah** on Monday, June 8, 2009 at 1:25pm.

Two dogs pull horizontally on ropes attached to a post; the angle problem 1 between the ropes is 60.0 degrees. If dog A exerts a force of 270N and dog B exerts a force of 300N find the magnitude of the resultant force and the angle it makes with dog A's rope.

- Physics -
**bobpursley**, Monday, June 8, 2009 at 1:33pm
You have a SAS triangle problem. You need the third side, and an angle.

Draw this out in a head to tail vector on vector.

one vector 270 at zero degrees (dogA). Next, starting at the end of that vector, a 300N at 60 deg upward (the angle then in the triangle is 120 deg).

First, the length of the other side:

Law of cosines..

R^2=a^2+b^2 -2abcos120

you know a, b find R

Then the angle between the dogA and the resultant.

SinAngle/opposite side=Sin120/R

where the opposite side in this triangle is 300

solve for the angle.

- Physics -
**Henry**, Wednesday, July 15, 2015 at 8:16pm
F = 270[0o] + 300[60o]

F = 270+300*Cos60 + 300*sin60=420+259.8i

= 494N.[31.74o].

F = 31.74o above dog A.

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