how many atoms of tungsten are in 504.56 g of tungsten(IV)acetate.
i attempted this problem but ended up with atoms of tungsten(IV) acetate in tungsten(IV) acetate instead of atoms of just tungsten in tungsten(IV) acetate.
please help
thanks
WRite the formula:
W(acetate)4
so there are the same number of atoms of tungsten as is molecules of tungsten acetate.
moles=mass/molmass
molecules tungsten acetate=moles*avagnumber
atomstungsten=moles*avanumger
acetateions=moles*4*avanumber.
To calculate the number of atoms of tungsten in tungsten(IV)acetate, you need to use the concept of molar mass and Avogadro's number.
Step 1: Determine the molar mass of tungsten(IV)acetate.
To do this, find the atomic masses of tungsten (W), carbon (C), and oxygen (O) from the periodic table:
Atomic mass of W = 183.84 g/mol
Atomic mass of C = 12.01 g/mol
Atomic mass of O = 16.00 g/mol
The molecular formula of tungsten(IV)acetate is (W(C2H3O2)4), which means there are four acetate (C2H3O2) groups bonded to one tungsten atom.
Molar mass of tungsten(IV)acetate = (Atomic mass of W) + (Atomic mass of C x 2) + (Atomic mass of H x 3 x 2) + (Atomic mass of O x 2 x 4)
= (183.84) + (12.01 x 2) + (1.01 x 3 x 2) + (16.00 x 2 x 4)
= 744.63 g/mol
Step 2: Calculate the moles of tungsten(IV)acetate.
Moles = Mass / Molar mass
= 504.56 g / 744.63 g/mol
≈ 0.678 mol
Step 3: Determine the number of atoms of tungsten.
Avogadro's number states that there are 6.022 x 10^23 particles (atoms, molecules) in one mole of any substance.
Number of atoms = Moles x Avogadro's number
= 0.678 mol x (6.022 x 10^23)
≈ 4.084 x 10^23 atoms
Therefore, there are approximately 4.084 x 10^23 atoms of tungsten in 504.56 g of tungsten(IV)acetate.