Posted by **Cassie** on Saturday, June 6, 2009 at 11:44am.

Which is the equation in standard form of the line that is perpendicular to 6x-8y=2 and contains (-1,4)?

a) x - 4y = -17

b) 4x + 3y = 8

c) 3x + 4y = 13

d) 4x - 3y = -16

Please explain how to do this problem. Thanks! :)

- Algebra -
**Reiny**, Saturday, June 6, 2009 at 11:56am
here is an easy way:

first of all I would reduce the given line to 3x - 4y = 1

since the slopes must be opposite reciprocals, the new equation must be

4x + 3y = c

the only one that has that pattern is b)

test if (-1,4) lies on it.

LS = -4 + 12 = 8 = RS

OK then!

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