Post a New Question

Pre-Algebra

posted by on .

How can I solve this problem, I'm stuck on it:

Approximate to the nearest hundreth by interpolation

5*square root of 84.4

Thanks
-MC

  • Pre-Algebra - ,

    You probably need to use some tables to interpolate.

    But without those, nine squared is 81
    10 squared is 100

    Using that, which is rather loose, then

    the difference in 84.4 and 81 is 3.4
    the difference in 81 and 100 is 19
    so 3.4/19 = x/1 where x is the addition to 9.0

    x=.179

    Square root of 84.4 then is 9.18 to the nearest hundredth, approximately

  • Pre-Algebra - ,

    Thank you so much bobpursley!
    -MC

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question