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Post a New Question | Current Questions | Chat With Live Tutors
Homework Help Forum: Chemistry
Posted by Alex on Friday, June 5, 2009 at 2:40am.
4.How many grams of calcium chloride can be prepared if a student uses 500g if calcium carbonate and 2.00L of a 4.00 Mol/L sodium chloride solution in the reaction.??
5. 2KMnoO4 + 5 H2C2O4<----need to use this
Concentration of 0.24L KMnO4 solution required to oxidize 2.7g of Oxalic Acid???
6.What volume of 0.100mol/L aqueous sodium hydroxide(NaOH) is neutralized by 500ml of 0.200mol/L hydrochloric acid(HCI) ??
7.When 10.0g of potassium chlorate,KCIO3,decomposes,what volume of oxygen is obtained(at 18C and 750 mm HG pressure) ??
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- Chemistry - MathMate, Friday, June 5, 2009 at 8:25am
4.How many grams of calcium chloride can be prepared if a student uses 500g if calcium carbonate and 2.00L of a 4.00 Mol/L sodium chloride solution in the reaction.??
Alex, could you check the question?
Calcium carbonate does not react directly with sodium chloride to make calcium chloride, just like sea water does not dissolve lime-stone. Otherwise many parts of the world would be eroded by the sea. However, it is easily possible to make calcium chloride from hydrochloric acid through the reaction:
CaCO3 + 2HCl -> CaCl2 + H2O
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- Chemistry - MathMate, Friday, June 5, 2009 at 8:50am
- Chemistry - MathMate, Friday, June 5, 2009 at 8:55am
6.What volume of 0.100mol/L aqueous sodium hydroxide(NaOH) is neutralized by 500ml of 0.200mol/L hydrochloric acid(HCI) ??
NaOH + HCl --> NaCl + H2O
From
500 ml of 0.2 mol/l of HCl contains
(500/1000)*0.2=0.1 mole of HCl,
and
1 litre of 0.1 mol/l of NaOH contains 0.1 mole of NaOH,
we conclude that 1 litre of 0.1 mol/l NaOH aqueous solution is required.
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- Chemistry - MathMate, Friday, June 5, 2009 at 9:03am
7.When 10.0g of potassium chlorate,KCIO3,decomposes,what volume of oxygen is obtained(at 18C and 750 mm HG pressure) ??
2KClO3 + heat -> 2KCl + 3O2
Managanese dioxide is used as a catalyst for this reaction.
Molecular weight of KClO3
=39+35.5+3*16=122.5
Number of moles of oxygen produced
=10/(2*122.5)*3
=0.1224 mole
Volume of oxygen
= 0.1224*22.4 l.
= 2.74 litres
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- Chemistry - MathMate, Friday, June 5, 2009 at 9:03am
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Erratum: Manganese dioxide
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- Chemistry - Alex, Friday, June 5, 2009 at 2:03pm
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yes..for #4 it is hydrochloric acid i forgot to put it in,how would u find the grams of calcium chloride???Thank you MathMate
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