Alg2/Trig
posted by Vincent .
Find the exact value of the trigonometric function given that sin u = 5/13 and cos v = 3/5. (Both u and v are in Quadrant II.)
Find csc(uv).
First of all, I drew the triangles of u and v. Also, I know the formula of sin(uv) is sin u * cos v  cos u * sin v. However, I am confused of what you do when you have csc(uv). Would you do csc u * sec v  sec u * csc v?
Thanks.

no, that is wishful thinking.
csc(uv) = 1/sin(uv)
so work out the sin(uv) according to your formula, the take the reciprocal of your final fraction. 
Okay, I worked sin(uv) out and I got 33/65. Would I then flip it over and get 65/33 as my final answer?

yes, that is also what I got
(and I checked it by finding the actual angles) 
Okay thanks for your help!