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January 28, 2015

January 28, 2015

Posted by **<3** on Thursday, June 4, 2009 at 10:44pm.

- Math! -
**Reiny**, Thursday, June 4, 2009 at 11:01pmI assume you made a diagram.

let the time passed since noon be t hours

in that time ship A has traveled 25t n-miles , and ship B has traveled 16t n-miles

let the distance between them be d n-miles

I see a right-angled triangle with base of

50 + 25t, a height of 16t and a hypotenuse of d

d^2 = (50+25t)^2 + (16t)^2

at 6:00 pm, t = 6

d^2 = 221.847

2d(dd/dt) = 2(50+25t)(25) + 2(16t)(16)

so at 6:00 pm

dd/dt = [2(50+150)(25) + 2(96)(16)]/221.847

= 58.923

check my arithmetic

- Math! -
**<3**, Thursday, June 4, 2009 at 11:14pmThis answer isn't right either & I don't understand how you got d^2 = 221.847.

- Math! -
**Reiny**, Thursday, June 4, 2009 at 11:26pmthat d^2 = 221.847 was a typo

should have said d = 221.847

As you can see further down I used it as such.

Alos in my third last line of my previous post I should have divided by 2(221.847) to get

29.46 instead of 58.923

- Math! -
**<3**, Thursday, June 4, 2009 at 11:34pmYeah. That's better. Thanks again!

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