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April 17, 2014

April 17, 2014

Posted by **Sarah** on Thursday, June 4, 2009 at 9:06pm.

- Physics -
**MathMate**, Thursday, June 4, 2009 at 10:00pmSince he shoots horizontally, the drop starts the moment the bullet leaves the rifle, at the rate of g (acceleration due to gravity).

For (a) and (b), calculate the time t the bullet is in the air using the horizontal speed, then calculate drop using

S=ut+at^2/2

where a=-g, and u the muzzle velocity.

- Physics -
**Sarah**, Thursday, June 4, 2009 at 10:38pmwhat is U? and i dont have time so i need to find it and what do i put in for S to find t? sorry im so confused

- Physics -
**MathMate**, Thursday, June 4, 2009 at 10:44pmu is the initial velocity = muzzle velocity.

The formula is to find S, the distance the bullet drops vertically.

- Physics -
**Sarah**, Thursday, June 4, 2009 at 10:55pmso u would = 750 ft/s, but there is no time so how can you solve for S if t is not available

- Physics -
**MathMate**, Thursday, June 4, 2009 at 11:01pmThe time is simply the horizontal distance divided by the muzzle speed, since the rifle is aimed horizontally, so cos0=1.

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