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August 1, 2014

August 1, 2014

Posted by **B.B.** on Thursday, June 4, 2009 at 12:30pm.

- Math -
**Count Iblis**, Thursday, June 4, 2009 at 3:01pmWithout using the formal definition of the integers and of the numbers 6 and 8, you can't prove that 8 > 6. Any demonstration that doesn't use the definitions will end up using what it is supposed to verify.

So, in your case, if you don't use the fact that 8 > 6, you can't construct the sets A and B in the first place. E.g., you could just as well have defined:

A = {8,7,6,5,4,3,2,1}

B= {8,5,4,3,2,1}

Then, analogous to your proof, I can use the symbol 6 to represent n(A) and the symbol 8 to represent n(B).

Then B is a subset of A, so you could say that 8 < 6.

- Math -
**B.B.**, Thursday, June 4, 2009 at 3:38pmThanks for the help.

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