Posted by Hope on Wednesday, June 3, 2009 at 3:57pm.
Solve the compound inequality.
9 (less than or equal to) 3x  9 (less than or equal to) 15
I totally forget how to solve inequalities, please help! Thanks!

Algebra  bobpursley, Wednesday, June 3, 2009 at 4:04pm
9<= 3x9<=15
add 9 to each component.
0<=3x<=24
divide by 3
0>x>8
check that.

Algebra  ~Emily~, Wednesday, June 3, 2009 at 4:25pm
This is what I got:
0(greater than or equal to)x(greater than or equal to) 8
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
(less than or equal to)=(LTorET)
(greater than or equal to)=(GTorET)
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
1. I broke it up into 2 problems
9(LTorET)3x9 and 3x9(LTorET)15
2.I solved the first problem by adding 9 to both sides. Then I had
0(LTorET)3x
3.I divided both sides by 3 which equaled
0(GTorET)x
~~note: Flip the sign when dividing or multiplying by a negative~~
4. I did the same type of thing with
3x9(LTorET)15 which equaled
x(GTorET)8
5. I got the answer:
0(GTorET)x(GTorET)8
OR
x(LTorET)0 and x(GTorET)8
~~however you want to write that~~
If you go to google and look up how to solve compound inequalities there are some good pages there.

Algebra  bobpursley, Wednesday, June 3, 2009 at 4:35pm
8 on the right is correct.
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