Posted by **Hope** on Wednesday, June 3, 2009 at 3:57pm.

Solve the compound inequality.

-9 (less than or equal to) -3x - 9 (less than or equal to) 15

I totally forget how to solve inequalities, please help! Thanks!

- Algebra -
**bobpursley**, Wednesday, June 3, 2009 at 4:04pm
-9<= -3x-9<=15

add 9 to each component.

0<=-3x<=24

divide by -3

0>x>8

check that.

- Algebra -
**~Emily~**, Wednesday, June 3, 2009 at 4:25pm
This is what I got:

0(greater than or equal to)x(greater than or equal to) -8

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

(less than or equal to)=(LTorET)

(greater than or equal to)=(GTorET)

~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

1. I broke it up into 2 problems

-9(LTorET)-3x-9 and -3x-9(LTorET)15

2.I solved the first problem by adding 9 to both sides. Then I had

0(LTorET)-3x

3.I divided both sides by -3 which equaled

0(GTorET)x

~~note: Flip the sign when dividing or multiplying by a negative~~

4. I did the same type of thing with

-3x-9(LTorET)15 which equaled

x(GTorET)-8

5. I got the answer:

0(GTorET)x(GTorET)-8

OR

x(LTorET)0 and x(GTorET)-8

~~however you want to write that~~

If you go to google and look up how to solve compound inequalities there are some good pages there.

- Algebra -
**bobpursley**, Wednesday, June 3, 2009 at 4:35pm
-8 on the right is correct.

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