Posted by Saira on Tuesday, June 2, 2009 at 6:49pm.
i need help with a rate law question:
The reaction is
2ClO2(aq) + 2OH -(aq)---> ClO3-(aq)+ ClO2-(aq) + H2O(l)
INITIAL RATE= 5.75*10^-2
INITIAL RATE= 2.30*10^-1
INITIAL RATE= 1.15*10^-1
a) determine the rate law and the value of the rate constant.
b) what would be the initial rate for an experiment with [ClO2]0= 0.175 mol/L and [OH-]0= 0.0844 mol/L?
- Chemistry - Saira, Tuesday, June 2, 2009 at 6:50pm
WHen i did it the answers i got was order of reaction m= 2 and k = 4.6
Can someone please double check
- Chemistry - DrBob222, Tuesday, June 2, 2009 at 7:53pm
Thanks for your answer.
I don't get that.
I have an order of 3 and k = 230
rate = k(ClO2^-)x(OH^-)y.
For x I have 2. For y I have 1. The order overall is 3. Check my work.
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