Monday
April 21, 2014

Homework Help: Chemistry

Posted by Saira on Tuesday, June 2, 2009 at 6:49pm.

i need help with a rate law question:

The reaction is

2ClO2(aq) + 2OH -(aq)---> ClO3-(aq)+ ClO2-(aq) + H2O(l)

Experiment 1:

[ClO2]0= 0.0500
[OH-]0= 0.100
INITIAL RATE= 5.75*10^-2

Experiment 2:

[ClO2]0= 0.100
[OH-]0= 0.100
INITIAL RATE= 2.30*10^-1

Experiment 3:

[ClO2]0= 0.100
[OH-]0= 0.050
INITIAL RATE= 1.15*10^-1

a) determine the rate law and the value of the rate constant.

b) what would be the initial rate for an experiment with [ClO2]0= 0.175 mol/L and [OH-]0= 0.0844 mol/L?

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