How many grams does 3.45 moles of FeCl3 weigh? I got 162.2 grams.
It is wrong. Please post your calculations and I will find your error.
Fe=55.85 Cl=35.45x3=639.2 total: 695.05.
695 moles 1 gram 3.45 mole
x x
1 mole
I actually got a different answer this time, because I did the work differently. Basically I don't know how to do this sort of problem, so I just need a basic rundown on how to do it. Thanks for your help.
OK, your totals for the atoms are 55.85+3*35.45=162.2 grams per mole.
You have 3.45 moles, so you multiply the grams/mole by that. It is 559grams.
Practice this here for a few minutes.
http://www.convertunits.com/from/grams/to/moles
Do it for FeCl2, and C6H12O6
To determine the weight of a substance, you can use the concept of molar mass. Molar mass is the mass of one mole of a substance, expressed in grams.
In this case, you want to find the weight of 3.45 moles of FeCl3. To do this, you need to know the molar mass of FeCl3, which is the sum of the atomic masses of iron (Fe) and chlorine (Cl).
The atomic masses are as follows:
- Iron (Fe) = 55.845 g/mol
- Chlorine (Cl) = 35.453 g/mol
So, the molar mass of FeCl3 can be calculated as:
Molar mass of FeCl3 = (1 x Atomic mass of Fe) + (3 x Atomic mass of Cl)
= (1 x 55.845 g/mol) + (3 x 35.453 g/mol)
= 162.291 g/mol (rounded to three decimal places)
Now that you know the molar mass of FeCl3, you can calculate the weight of 3.45 moles by multiplying the molar mass by the number of moles:
Weight = Number of moles x Molar mass
= 3.45 moles x 162.291 g/mol
= 559.907 g (rounded to three decimal places)
Therefore, the weight of 3.45 moles of FeCl3 is approximately 559.907 grams, which is different from your calculated value of 162.2 grams. Please double-check your calculations, as they may contain an error.