Posted by Sophie on Tuesday, June 2, 2009 at 3:48pm.
Find an equation of the line that bisects the obtuse angles formed by the lines with equations 3xy=1 and x+y=2.
a. (3√2 +√10)x(√10 + √2)y2√10+√2=0
b. (3√2  √10)x+(√10  √2)y+2√10+√2=0
c. (3√2 + √10)x+(√10  √2)y+2√10  √2=0
d. (3√2 + √10)x(√10 + √2)y2√10√2=0
i'm not sure on this one!

Math  Reiny, Tuesday, June 2, 2009 at 4:57pm
before I answer this question, I have to establish if you know
1. that slope = tan(angle the line makes with the xaxis)
2. if m1 and m2 are the slopes of 2 nonparallel lines, and theta is the acute angle between them, then
tan(theta) = │(m1  m2)/(1 + m1m2)│
If not please watch this short video.
http://www.slideshare.net/nsimmons/11x1t0507anglebetweentwolines
3. tan(2A) = 2tanA/(1tan^2 A)
I also noticed that in the first answer given, the slope of the line is
(3√2+√10)/(√10+√2) which when rationalized is (1+√5)/2 which is the answer that I got for the required line.
So you might have obtained the correct slope of the new line without realizing it.
Let me know if you need more help.

Math  sophie, Tuesday, June 2, 2009 at 6:11pm
okay thanks
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