Posted by Alicia on Monday, June 1, 2009 at 7:48pm.
Help please....Please Simplify
(3a^5 b^6)^4 (a^7b^0)^3
any ideas? thanks in advance!

Algebra  MathMate, Monday, June 1, 2009 at 8:00pm
First, I will assume that the 3 at the beginning will not be raised to the 5th power.
A little revision of the law of indices is in order:
(ab)^n = a^n . b^n
this will apply to the ^4 and ^3 outside of the parentheses.
a^n=1/a^n
This will apply to the term a^5
b^0 = 1
for all values of b except 0.
(3a^5 b^6)^4 (a^7b^0)^3
=(3b^6/a^5)^4 (a^7 . 1)^3
=(3)^4 (b^6)^4 /(a^5)^4 (a^7)^3
= (3)^4 (b^24)/(a^20) (a^21)
= ...
I will let you take it from here.
Post your answer for a check if you wish.
=

Algebra  Alicia, Monday, June 1, 2009 at 8:18pm
Ok thanks! I got 81ab^24 Is this correct? Thanks!

Algebra  MathMate, Monday, June 1, 2009 at 9:56pm
Excellent, the answer is correct.
Do start the problem over to understand every step.
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