Posted by Kelly on Monday, June 1, 2009 at 4:52pm.
So I'm doing a lab about simple harmonic information and I have to answer questions at the end of a lab were I'm provided this question to answer
here's a step that's not the actual question but the question makes reference to it
Using the pointer and the scale, note the equilibrium position of your mass on the spring, pull the mass down a given distance, record it, and release the mass. Record the position that the mass rises to. Do this for each mass.
Here's a question that asked me about step 3 which is not the actual question I have but my answer helps answer my question
So here was question 1
How did the distance above and below the equilibrium positions compare for each of the masses in step 3?
here's my answer
1. When we performed step three in the procedure that when we pulled the mass spring system down 4.0 cm from the equilibrium position with mass that it went past this equilibrium position 4.0 cm. For every single different mass that was used to conduct this experiment the same thing also occurred.
HERE'S MY QUESTION...
Using your experimentally determined spring constant, your largest mass, and your amplitude for that mass from step 3, calculate
a. The total eneergy of your spring-mass system;
b. the velocity of the mass when it passes through its equilibrium position (E total = E kinetic)
C. The potential energy and kinetic energy of your Simple Harmonic Oscillator when its displacement is half the amplitude. (x=A/2 E potential = 1/2 kx^2 & E total = E potential + E kinetic)
d. The velocity of the mass when it displacemnt is half the amplitude.
ok and heres my data
largest mass = .117 kg
Amplitude = 4.0 cm
100 cm = m
(4.0 cm) / (100 cm) = .04 m
here's all of my data on for this mass that I don't may help or may not help asnwer this question
Force of gravity = -.49 N
x (this distance is the x I pulled down the spring to find the observed period that I found by finding the time for 10 oscillations) = -.01 m
spring constant k = 49 N/m
T observed = .33 s
T calculated = .20s
Ok I don't know how to answer these questions... I don't know what formula to use for E total when it's not direcly given in the question like in point a
If you could please show me how to do this and all of the formulas used and proper sig figs....
Thank you for the help!
- physics - Kelly, Monday, June 1, 2009 at 4:53pm
i don't know why it's not posting Oo
- physics - MathMate, Monday, June 1, 2009 at 4:59pm
Try posting just the part missing. We're listening.
- physics - Damon, Monday, June 1, 2009 at 7:35pm
You can not copy and paste on to this screen unless you are a teacher Kelly.
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