Posted by reese on Sunday, May 31, 2009 at 11:21am.
The distance of 36.3 m from the building and the horizontal velocity tells you how long the ball was in the air.
This calculated time, together with the acceleration due to gravity should enable you to calculate the drop in height of the ball.
The time taken to travel the horizontal distance of 36.3m derives from t = 36.3/17 = 2.135 sec.
The height of the building then derives from
h = Vo(t) + gt^2/2 or
h = 0(2.135) + 4.9(2.135)^2 or
h = 22.33m.
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