Posted by **reese** on Sunday, May 31, 2009 at 11:21am.

A ball thrown horizontally at 17.0 m/s from the roof of a building lands 36.3 m from the base of the building.

How tall is the building?

could someone PLEASE tell me how to go about solving this problem!

- physics -
**MathMate**, Sunday, May 31, 2009 at 11:51am
The distance of 36.3 m from the building and the horizontal velocity tells you how long the ball was in the air.

This calculated time, together with the acceleration due to gravity should enable you to calculate the drop in height of the ball.

- physics -
**TchrWill**, Sunday, May 31, 2009 at 12:11pm
The time taken to travel the horizontal distance of 36.3m derives from t = 36.3/17 = 2.135 sec.

The height of the building then derives from

h = Vo(t) + gt^2/2 or

h = 0(2.135) + 4.9(2.135)^2 or

h = 22.33m.

## Answer this Question

## Related Questions

- physics - A ball thrown horizontally at 13.0m/s from the roof of a building ...
- Physics - A ball thrown horizontally at 18.3 m/s from the roof of a building ...
- Physics - A ball thrown horizontally at 22.2 m/s from the roof of a building ...
- Physics - A ball is thrown horizontally at 12.2 m/s from the roof of a building ...
- physics - A ball thrown horizontally at 22.3 m/s from the roof of a building ...
- Physics - A ball thrown horizontally at 22.3 m/s from the roof of a building ...
- Physics - A ball is thrown horizontally from the roof of a building 55 m tall ...
- physics - A ball is thrown horizontally from the roof of a building 59.0 tall ...
- physics - A ball is thrown horizontally from the roof of a building 33.0 m tall ...
- physics - A ball is thrown horizontally from the roof of a building 60 m tall ...

More Related Questions