Posted by Gweedo8 on Sunday, May 31, 2009 at 11:08am.
ml of aluminum? Hmmmm. So get the denstiy of aluminum, and convert the ml to mg. This is odd, check your problem.
Now convert the mass of Al to moles.
2Al+ 3S>>>Al2S3
Notice for each mole of S, you need 2/3 mole of Al. If you do not have that much of Al, then Al is the limiting reageant.
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