Monday

March 30, 2015

March 30, 2015

Posted by **hannah** on Sunday, May 31, 2009 at 11:05am.

please help, I don't understand how to do this problem!

- algebra HELP -
**drwls**, Sunday, May 31, 2009 at 12:04pmLet's say Mary used X ml of the 60% solution and Y ml of the 20% solution. You have two requirements:

X + Y = 100 (the total amount needed), and

0.6X + 0.2Y = 52 (the amount of a alcohol in the final mixture)

Solve those two equations in two unknowns. One way to do that would be to substitute 100 - X for Y in the second equation.

0.6X + 20 -0.2X = 52

0.4X = 32

etc

**Answer this Question**

**Related Questions**

Algebra (please help!) - Mary has a solution that is 60% alcohol and another ...

math - Mary has a solution that is 60% alcohol and another that is 20% alcohol. ...

Math - 1. In the lab, Deon has two solutions that contain alcohol and is mixing ...

Algebra 1 - A lab technician has a 15 percent alcohol solution and a 35 percent ...

algebra - A laboratory assistant is asked to mix a 30% alcohol solution with 21 ...

math - A solution of alcohol and water is a% alcohol where a = 40. The solution ...

math - in the lab, tom has two solutions that contain alcohol and is mixing them...

algebra - moonshine has 50 liters of a 70% alcohol solution.how many liters of ...

math - A 5% alcohol solution is mixed with 15% alcohol solution to make a 25mlof...

Alegebra - Solution A is 60% alcohol and Solution B is 30% alcohol. How much of ...