Saturday

August 30, 2014

August 30, 2014

Posted by **sam** on Friday, May 29, 2009 at 7:50am.

the graph of position vs time and velocity vs time are given.

The red ball has a linear graph and the coordinates are (0,0), (1,5), (2,10), (3,15), and (4,20)

for the blue ball:(0,0), (1,1), (2,2.5), (3,4.5), (4,7)

it is asked:

If the motion was allowed to continue the blue (lower) ball would reach the finish line (20m) at some time Δt after the red ball. What is Δt?

i though that it would take the blue ball around 9 seconds to reach the finish line,but I don't think this is right

thanks!

- physics -
**sam**, Friday, May 29, 2009 at 8:13amhere is the graph given can be seen if you search

"constant velocity versus constant acceleration" on google- its the first link

- physics -
**PC**, Friday, May 29, 2009 at 9:21amSam, The response to

"physics - sam, Thursday, May 28, 2009 at 11:43pm"

had been posted last night, even with a suggested correction that you have made this morning.

Would you like to check back before we continue?

- physics -
**PC**, Friday, May 29, 2009 at 9:22amphysics - PC, Friday, May 29, 2009 at 12:18am

Here is a copy of the previous response.

> (0,0), (1,1), (2,2.5), (3,5), (4,7)

Could you check the data for the blue ball to see if it is not:

(0,0), (1,1), (2,2.5), **(3,4.5)**, (4,7)

If that's the case, you will find that the function of the blue ball is

y=f(x)=(x^2+3x)/4

in which case you can easily solve for

f(x)=20

- physics -
**sam**, Friday, May 29, 2009 at 9:26amI did that, and the answer came out to be 10.57, which isn't right.

I wasn't sure if a picture of it would help at all?

- physics -
**PC**, Friday, May 29, 2009 at 12:28pmI have uploaded a graph but I am unable to show the link as I do not have privileges to do so. Sorry.

- physics -
**Anonymous**, Friday, May 29, 2009 at 12:41pmThe answer is the solution to the equation

(x^2+3x)/4=20

Do you have difficulties finding the solution to the above equations?

- physics -
**MathMate**, Saturday, May 30, 2009 at 11:08pmHello Sam, here'is the link to the graph you requested:

http://i263.photobucket.com/albums/ii157/mathmate/parabola.png

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