Posted by sc on Friday, May 29, 2009 at 2:41am.
I will assume there is a typo and you meant
y = x^2 + 4x - 8
take 1/2 the coefficient of the x term, square it, then add and then subtract it
( 1/2 of 4 is 2 and then squared would be 4)
y = x^2 + 4x + 4 - 4 - 8
the first three terms are now a perfect square
y = (x+2)^2 - 12
compare this with
y = a(x-p)^2 + q which has vertex (p,q) and you can conclude that the vertex of
y = (x+2)^2 - 12 is (-2,-12)
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