Wednesday

August 20, 2014

August 20, 2014

Posted by **Algebra 2** on Thursday, May 28, 2009 at 2:45pm.

I have no idea how to turn this into SRform

2187^(1/3) - 2(24)^(1/3)

I saw I could do this

2187^(1/3) - 2(4*6)^(1/3)

2187^(1/3) - 4(6)^(1/3)

then I do this

2187^(1/3)/ (6)^(1/3)

and I don't get a whole number so I can conclude that...

I can never get a whole number(6)^(1/3) = 2187^(1/3) which I need to do becasue 2(24)^(1/3) SRform is 4(6)^(1/3) and I can not get a whole number(6)^(1/3) for the SRform of 2187^(1/3) so what do I do?

I really don't understand the point of SRform either

please show me how to do this problem step by step and the reasoning

thanks

- Algebra 2 -
**bobpursley**, Thursday, May 28, 2009 at 3:00pm2187^(1/3) - 2(24)^(1/3)

I notice 24 is a perfect cube (8) times 3.

2187^(1/3) - 2(8*3)^(1/3) so I look at the 2187 to see if an 3 will divide out. Wallah! 2187=729*3 = 243*3*3=81*3*3*3 that is enough, knowing 81 ia 3*27

Now it is reduced to ...

(3*3^3*3^3)^1/3-6(3)^1/3

or

(9-6)(3)^1/3= 3*3^1/3

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