if light touching a surface has an intensity of about 1000W/m^2, how many numbers of photons per m^2 per sec does this show?
wavelength of P=600nm
Figure the energy of one photon with that wavelength.
E=hf=hc/lambda
then divide the given energy by the energy per photon.
thanks!
To find the number of photons per square meter per second for light with a given intensity, you can use the formula:
Number of photons = Power / (Energy per photon x Area x Time)
Given:
Intensity of light (Power per unit area) = 1000 W/m^2
Wavelength of light (λ) = 600 nm = 600 x 10^-9 m
First, we need to calculate the energy per photon using the formula:
Energy per photon = Planck's constant (h) x Speed of light (c) / wavelength
h = 6.626 x 10^-34 J·s (Planck's constant)
c = 3 x 10^8 m/s (Speed of light)
Now we can calculate the energy per photon:
Energy per photon = (6.626 x 10^-34 J·s) x (3 x 10^8 m/s) / (600 x 10^-9 m)
Next, we can calculate the number of photons per square meter per second using the given intensity:
Number of photons = (1000 W/m^2) / (Energy per photon x Area x Time)
Here, the Area can be taken as 1 square meter, and Time can be taken as 1 second.
Number of photons = (1000 W/m^2) / (Energy per photon x 1 m^2 x 1 sec)
After calculating the energy per photon, you can substitute the values into the equation to find the number of photons per square meter per second.