Posted by **sh** on Thursday, May 28, 2009 at 7:13am.

60% of the hockey players are from Eastern Canada and 40% are from Western Canada. 18% of the Eastern players and 12% of the Western players go on to play in the NHL. If a randomly chosen NHL player is selected, what is the probability that he is from Western Canada?

P(NHL|W)=(0.4x0.12)/(0.4x0.12)(0.18x0.6) ?

- math -
**PC**, Thursday, May 28, 2009 at 7:45am
Your answer tells me that you are in the right direction, but there is something wrong with the expression:

(0.4x0.12)/(0.4x0.12)(0.18x0.6)

because it evaluates to 9.259 > 1.

Think of a bag of 4 red and 6 blue marbles. The chances of drawing a red would be

4/(4+6)=0.4.

Rework your expression and I am sure you'll get the right answer.

- math -
**Damon**, Thursday, May 28, 2009 at 7:45am
yes,y ou have it right

say there are 100 total

60 E

40 W

E in NHL = .18*60 = 10.8

W in NHL = .12*40 = 4.8

Total = 10.8+4.8 = 15.6

fraction W in total = 4.8/15.6

- math -
**Damon**, Thursday, May 28, 2009 at 7:47am
Oh, but you multiplied on the bottom instead of adding.

- math -
**sh**, Thursday, May 28, 2009 at 8:01am
Whoops, a typo. I finally got one of these questions right :)

Thank you!

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