Can you tell me what the empirical formulas are for
C2H6O4
N2O5
Hg2Cl2
C6H12
Thank you!
C2H6O4-> CH3O2
N2O5-> N2O5
Hg2Cl2-> HgCl
C6H12-> CH2
Sure, here are the empirical formulas for the compounds you mentioned:
C2H6O4: The empirical formula is CH2O because we can divide all the subscripts by 2 to simplify it. It's like a math problem, but with molecules!
N2O5: The empirical formula is NO2 because we can't simplify it any further without breaking any chemical laws. It's already as simple as it can be, just like me!
Hg2Cl2: The empirical formula is HgCl because we can divide all the subscripts by 2 to make it simpler. HgCl might sound like the name of a new superhero, but it's just a chemical formula!
C6H12: The empirical formula is CH2 because we can divide all the subscripts by 6 to make it more concise. It's like saying "less is more" but for molecules!
Hope this helps, and remember, chemistry is all about simplifying things to their most basic form. Just like trying to simplify your life by using humor, right?
Of course! To find the empirical formulas of these compounds, we need to determine the simplest whole-number ratio of atoms present in each molecule.
Let's start with C2H6O4:
1. Identify the number of each type of atom in the molecule:
- 2 carbon atoms (C)
- 6 hydrogen atoms (H)
- 4 oxygen atoms (O)
2. Find the greatest common factor (GCF) of these numbers. In this case, the GCF of 2, 6, and 4 is 2.
3. Divide each count by the GCF to get the simplest whole-number ratio:
- Carbon: 2/2 = 1
- Hydrogen: 6/2 = 3
- Oxygen: 4/2 = 2
Therefore, the empirical formula for C2H6O4 is CH3O2.
Moving on to N2O5:
1. Identify the number of each type of atom in the molecule:
- 2 nitrogen atoms (N)
- 5 oxygen atoms (O)
2. The numbers in this case do not have a common factor other than 1, so we keep them as they are.
Therefore, the empirical formula for N2O5 is N2O5 itself.
Now let's consider Hg2Cl2:
1. Identify the number of each type of atom in the molecule:
- 2 mercury atoms (Hg)
- 2 chlorine atoms (Cl)
2. Similar to N2O5, the numbers in this case do not have a common factor other than 1, so we keep them as they are.
Therefore, the empirical formula for Hg2Cl2 is Hg2Cl2 itself.
Lastly, for C6H12:
1. Identify the number of each type of atom in the molecule:
- 6 carbon atoms (C)
- 12 hydrogen atoms (H)
2. We can divide all numbers by 6 to simplify further:
- Carbon: 6/6 = 1
- Hydrogen: 12/6 = 2
Hence, the empirical formula for C6H12 is CH2.
To summarize:
- C2H6O4 has an empirical formula of CH3O2
- N2O5 has an empirical formula of N2O5
- Hg2Cl2 has an empirical formula of Hg2Cl2
- C6H12 has an empirical formula of CH2
What do you mean to "tell me what the empirical formulas are?" These ARE the empirical formulas.
N2O5 is dinitrogen pentoxide.
Hg2Cl2 is mercury(I) chloride.
C6H12 could be hexane but it could also be a number of other compounds.
C2H6O4 could be one of hundreds of compounds.