Posted by Alessio on Wednesday, May 27, 2009 at 8:04am.
I believe you have posted this question before. The reason you may not have got an answer, as far as I am concerned, is that the question is not complete. Perhaps your teacher did not provide the information because it was obvious for him.
For anyone to be able to calculate/predict the fourth thickness, or even the thickness at any point around the circumference, we need to know the "function" that governs the thickness. It could be a sine or cosine variation, or it could be anything else.
Given only 3 or four thicknesses on the circumference, we could fit an infinite number of functions and so calculate an an uncountable number of answers.
If I have misinterpreted your question, let me know.
I too have seen this post several times, and as PC stated above, was not able to follow the problem as stated.
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